Legend entries all same color in Matlab 2015b

I just updated to Matlab 2015b, and the frustration has already begun.
I am making a simple scatter plot with multiple data sets. Each data set has a different color, but the legend shows points all in the same color. Example code showing problem below: (ONLY IN 2015b)
---------------
x = 1:1:100;
y1 = rand(1,100);
y2 = rand(1,100);
y3 = rand(1,100);
figure;
scatter(x,y1);
hold on;
scatter(x,y2,'*');
scatter(x,y3);
legend('random 1','random 2','random 3') ;
---------------
The different symbol choice on 'random 2' illustrates that the problem is only with color, and not with referencing the same handle for each.
Help much appreciated!
Maddie

4 Kommentare

Star Strider
Star Strider am 14 Sep. 2015
Definitely a bug. Nothing I tried (specifying colours and markers, returning handles and sending them to legend as arguments) alters what you saw. Since you discovered it, report it as a bug to TMW Tech Support.
the cyclist
the cyclist am 14 Sep. 2015
Agree on bug report suggestion. This code works properly for me in 2015a, and not 2015b.
Also found this bug. Easy to use the plot command but specify the marker type, i.e:
scatter(x,y,'r')
produces the same output as:
plot(x,y,'or')
The bug doesn't seem to affect the plot command.
Hello, found a way to show the color in the legend by forcing the `MarkerFaceColor` property:
h = scatter(x_data, y_data, area_data, 'green', 'filled', 'MarkerFaceColor', 'green');

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 Akzeptierte Antwort

Mike Garrity
Mike Garrity am 15 Sep. 2015

2 Stimmen

That sounds like bug 1283854. There's a patch and some workarounds at that link.

2 Kommentare

Madison Smith
Madison Smith am 15 Sep. 2015
That is exactly it. Thanks so much!
lis coffey
lis coffey am 4 Jul. 2016
i guess the problem is only with color, and not with referencing the same handle for each. Thanks \ Qwikfix \

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Weitere Antworten (4)

Jacob Kamminga
Jacob Kamminga am 28 Jun. 2016

3 Stimmen

From the bugreport, Use this workaround when the points within each scatter plot are different colors:
Call the legend function with two or more output arguments:
s1 = scatter(1:10,1:10,[],1:10);
hold on
s2 = scatter(2:11,1:10,[],26:35);
[h, ~] = legend('show');
Tony L.
Tony L. am 15 Sep. 2015

0 Stimmen

There must be a cleaner way to do this than the below, but gscatter seems to do the right thing:
x = 1:1:100;
y1 = rand(1,100);
y2 = rand(1,100);
y3 = rand(1,100);
g1 = repmat(1,length(y1),1);
g2 = repmat(2,length(y2),1);
g3 = repmat(3,length(y3),1);
ds = [x', y1', g1; x', y2', g2; x', y3', g3];
figure;
gscatter(ds(:,1), ds(:,2), ds(:,3));
legend('random 1','random 2','random 3') ;
SHR
SHR am 1 Mär. 2016

0 Stimmen

I have a similar issue. My data set is a table with multiple variables over time associated with specific locations. I wanted to graph all variables (y axis) over time on one scatter plot only for one location. Thus I converted the dates to DateNumebers and restricted the variables by location e.g., Y1-Znppm(SiteCat=='location_x'. The legend has the same symbol color. Is there an easier way to circumvent the bug?

1 Kommentar

Are you using R2015a? If so then apply the patch Mike indicated.

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Amir Mohammad Alizadeh
Amir Mohammad Alizadeh am 25 Mai 2016

0 Stimmen

and the bloody doesn't work. MATLAB is horrible

1 Kommentar

Which MATLAB version are you using? Did you apply the patch?

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