For loop with changing matrix

Hi,

I have a for loop (j= 1:years) in which matrix A changes per j. Matrix A is a matrix containing birthdates in column 8. Each row represents a person. Per year the total number of persons decreases, so every j+1, the rows in matrix A reduces.

I want to generate a new matrix B, representing the age of each person w.r.t. t= today. So matrix B should be of length(A), though this changes over j.

The output I want to get is a matrix B ,including all ages per j, so j columns.

Can anyone help me with this? I tried several codes, but it's not working...

Answer 1

[blaat]

You could use a cell array to store the ages per j. For example:

B = cell(1, years);
for j = 1:years
  % A is computed here
  B{j} = <operations on A(:, 8) to calculate age>;
end

Is this what you mean?

[Bas]

Thanks, this works. But now I want to check for every i= 1:length(A) of matrix B per j= 1:years if the value equals a value in matrix C. How can I compare this cell array with a normal matrix?

[blaat]

I'm assuming here that C has a single value per year j. You could then compare the value in a loop over the years:

for j = 1:years
  is_equal = B{j} == C; 
  % Do things with is_equal here...
end

Alternatively, you could use cellfun().