How to extract cell array in matlab
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hello.. Anyone does know? I need to extract from cell array (1x1 cell). For example > '22.11.2011 13:58:56.16' from this (1x1 cell).I want to extract time in second (:56) .How can I do. Thanks.
0 Kommentare
Akzeptierte Antwort
Fangjun Jiang
am 21 Nov. 2011
c={'22.11.2011 13:58:56.16','22.11.2011 13:58:40.16'};
d=datevec(c);
floor(d(:,6))
Weitere Antworten (3)
Sven
am 21 Nov. 2011
If you have strings of dates, use datevec as follows:
[Y, M, D, H, MN, S] = datevec('22.11.2011 13:58:56.16');
You'll notice that S has the value "56.1600", so floor(S) gives you the seconds
Andrei Bobrov
am 21 Nov. 2011
out = datevec({'22.11.2011 13:58:56.16'},'dd.mm.yyyy HH:MM:SS')
out = out(end)
OR
out = sprintf(':%d',out(end))
4 Kommentare
Walter Roberson
am 21 Nov. 2011
> datestr(datenum({'22.11.2011 13:58:56.16'},'dd.mm.yyyy HH:MM:SS.FFF'),':SS')
ans =
:56
>> char(cellfun(@(T) T(end-5:end-3), {'22.11.2011 13:58:56.16'},'Uniform',0))
ans =
:56
2 Kommentare
Walter Roberson
am 22 Nov. 2011
Based upon the previous answers, the following should also work:
datestr(datevec({'22.11.2011 13:58:56.16'}),':SS')
Siehe auch
Kategorien
Mehr zu Dates and Time finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!