How to count the amount of small squares in this picture?

 Akzeptierte Antwort

The given answers have problems with accuracy. One way to help with discrimination is to do some sort of template matching.
% the image
inpict = imread('https://www.mathworks.com/matlabcentral/answers/uploaded_files/1821039/image.png');
inpict = im2gray(inpict);
% the sub-image template
template = imcrop(inpict,[22.51 22.51 14.98 13.98]);
% get a correlation map describing
% where copies of the template are
C = normxcorr2(template,inpict);
mask = C > 0.5;
mask = bwareaopen(mask,9); % get rid of any specks
imshow(mask)
% count the peaks
N0 = bwconncomp(mask).NumObjects
N0 = 2925
Is that number plausible? The image isn't that large. We can just manually verify that there are 45x65 = 2925 copies of the template object. We can also do that programmatically:
% number of rows of objects
nv = smooth(max(C,[],2)) > 0.5;
nv = bwconncomp(nv).NumObjects
nv = 45
% number of columns of objects
nh = smooth(max(C,[],1)) > 0.5;
nh = bwconncomp(nh).NumObjects
nh = 65
% total
N = nv*nh
N = 2925
As is, the other examples produce an overestimate due to the occasional blob between objects, or content along the image boundary. When I tested them, the estimates were higher by about 100 or so.

1 Kommentar

Great!
This way get rid of the noise. I can get true result!

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Weitere Antworten (3)

Approximate Way:
image_input=imread('image file name');
image_bw=imbinarize(rgb2gray(image_input));
cc=bwconncomp(image_bw);
number=cc.NumObjects;
However, you can obtain the exact value by incorporating additional morphological and logical statements.
Image Analyst
Image Analyst am 15 Dez. 2024

0 Stimmen

It's a generic, general purpose demo of how to threshold an image to find blobs, and then measure things about the blobs, and extract certain blobs based on their areas or diameters.
Catalytic
Catalytic am 17 Dez. 2024
Bearbeitet: Catalytic am 17 Dez. 2024
BW=imbinarize(im2gray(imread('image.png')));
BW([1,end],:)=0;
BW(:,[1,end])=0;
BW=imopen(BW,ones(2));
nv=numAlong(BW,1)
nv =
45
nh=numAlong(BW,2)
nh =
65
total=nv*nh
total =
2925
function out=numAlong(BW,dim)
s=reshape( sum(BW,3-dim),[],1);
m=bwareaopen(s>max(s)/3,8);
out=bwconncomp(m).NumObjects;
end

Gefragt:

xie
am 15 Dez. 2024

Bearbeitet:

am 17 Dez. 2024

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