How to draw a network of nodes in circular formation with links between nodes in MATLAB?
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Haya Ali
am 25 Mai 2023
Kommentiert: Steven Lord
am 25 Mai 2023
I have a connectivity matrix
and I want a figure like this for my matrix.
How can I draw this using matlab? Please help.
A= [-1 -1 0 0 0 0 0 1 0 1 0 0 -1 1 1 -1 1 0 -1 1 -1 1 0;
1 -1 0 0 -1 0 -1 -1 0 0 -1 1 0 0 0 -1 1 -1 0 -1 -1 0 1;
0 1 -1 0 0 0 -1 1 -1 -1 -1 1 0 0 0 0 -1 0 0 -1 1 0 0;
1 0 0 1 0 0 -1 -1 0 0 0 1 -1 0 0 -1 1 -1 0 -1 -1 1 1;
-1 0 -1 0 1 0 0 1 0 1 0 -1 -1 1 1 0 0 0 0 1 1 0 0;
0 0 -1 0 0 0 1 0 0 1 0 0 1 -1 0 1 0 -1 1 1 -1 1 -1;
1 0 0 0 -1 0 0 1 0 1 -1 -1 -1 0 0 -1 -1 -1 0 0 -1 1 0;
1 0 1 0 1 0 0 1 0 0 1 1 -1 1 0 -1 0 0 0 0 -1 -1 0;
0 0 -1 -1 0 0 0 -1 0 -1 0 1 1 0 1 -1 1 -1 -1 -1 -1 0 0;
0 -1 -1 -1 1 0 0 -1 0 0 0 0 1 1 0 -1 1 0 0 -1 -1 0 1;
0 0 1 0 -1 0 -1 0 0 1 -1 -1 0 0 -1 0 -1 0 -1 1 1 1 1;
-1 0 0 1 1 0 -1 -1 0 -1 -1 1 -1 0 -1 0 0 1 0 1 1 0 1;
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 -1 0 0 -1 1 0 0 1 0 0 -1;
0 -1 0 -1 -1 0 0 -1 0 0 0 -1 1 1 0 0 1 0 0 -1 -1 0 0;
-1 0 -1 -1 1 0 0 1 0 1 0 -1 1 1 1 -1 0 0 -1 0 0 -1 -1;
-1 0 0 1 0 -1 -1 -1 0 -1 -1 1 -1 0 0 0 0 0 -1 1 1 1 1;
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 1 0 0 1 0 0 0 1 1 1 -1;
1 1 -1 0 -1 0 -1 1 0 1 -1 -1 -1 0 1 0 -1 -1 0 0 1 0 -1;
0 -1 1 1 0 0 -1 -1 1 1 0 -1 -1 1 0 -1 1 0 -1 0 0 1 0;
0 -1 -1 0 1 0 0 1 0 1 0 0 -1 1 0 1 1 0 -1 0 -1 0 -1;
1 1 -1 1 -1 0 0 0 -1 1 0 0 -1 0 -1 -1 -1 0 1 1 1 1 0];
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Akzeptierte Antwort
Steven Lord
am 25 Mai 2023
Use the Graph and Network Algorithms functionality included in MATLAB once you've corrected your adjacency matrix.
A= [-1 -1 0 0 0 0 0 1 0 1 0 0 -1 1 1 -1 1 0 -1 1 -1 1 0;
1 -1 0 0 -1 0 -1 -1 0 0 -1 1 0 0 0 -1 1 -1 0 -1 -1 0 1;
0 1 -1 0 0 0 -1 1 -1 -1 -1 1 0 0 0 0 -1 0 0 -1 1 0 0;
1 0 0 1 0 0 -1 -1 0 0 0 1 -1 0 0 -1 1 -1 0 -1 -1 1 1;
-1 0 -1 0 1 0 0 1 0 1 0 -1 -1 1 1 0 0 0 0 1 1 0 0;
0 0 -1 0 0 0 1 0 0 1 0 0 1 -1 0 1 0 -1 1 1 -1 1 -1;
1 0 0 0 -1 0 0 1 0 1 -1 -1 -1 0 0 -1 -1 -1 0 0 -1 1 0;
1 0 1 0 1 0 0 1 0 0 1 1 -1 1 0 -1 0 0 0 0 -1 -1 0;
0 0 -1 -1 0 0 0 -1 0 -1 0 1 1 0 1 -1 1 -1 -1 -1 -1 0 0;
0 -1 -1 -1 1 0 0 -1 0 0 0 0 1 1 0 -1 1 0 0 -1 -1 0 1;
0 0 1 0 -1 0 -1 0 0 1 -1 -1 0 0 -1 0 -1 0 -1 1 1 1 1;
-1 0 0 1 1 0 -1 -1 0 -1 -1 1 -1 0 -1 0 0 1 0 1 1 0 1;
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 -1 0 0 -1 1 0 0 1 0 0 -1;
0 -1 0 -1 -1 0 0 -1 0 0 0 -1 1 1 0 0 1 0 0 -1 -1 0 0;
-1 0 -1 -1 1 0 0 1 0 1 0 -1 1 1 1 -1 0 0 -1 0 0 -1 -1;
-1 0 0 1 0 -1 -1 -1 0 -1 -1 1 -1 0 0 0 0 0 -1 1 1 1 1;
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 1 0 0 1 0 0 0 1 1 1 -1;
1 1 -1 0 -1 0 -1 1 0 1 -1 -1 -1 0 1 0 -1 -1 0 0 1 0 -1;
0 -1 1 1 0 0 -1 -1 1 1 0 -1 -1 1 0 -1 1 0 -1 0 0 1 0;
0 -1 -1 0 1 0 0 1 0 1 0 0 -1 1 0 1 1 0 -1 0 -1 0 -1;
1 1 -1 1 -1 0 0 0 -1 1 0 0 -1 0 -1 -1 -1 0 1 1 1 1 0];
sz = size(A)
g = graph(A, 'upper');
Should your adjacency matrix be 21-by-21 or 23-by-23?
2 Kommentare
Steven Lord
am 25 Mai 2023
A = rand(23, 23) < 0.25; % Random adjacency matrix with roughly 25% nonzeros
nnz(A)./numel(A)
g = graph(A, 'upper');
plot(g)
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