How to add zeros diagonally in a matrix?

6 Ansichten (letzte 30 Tage)
Haya Ali
Haya Ali am 7 Mai 2023
Verschoben: VBBV am 9 Mai 2023
I am trying to add zeros diagonally in this matrix so it should become 23*23 matrix. But with my program it becomes 24*22 matrix. Please help to resolve the code.
close all; clear all; clc;
A= [0 0 0 1 0 -1 0 -1 -1 0 1 -1 0 0 1 -1 0 1 0 1 -1 0
0 1 1 1 0 0 -1 0 0 0 1 -1 1 -1 -1 1 0 -1 0 -1 1 0
-1 -1 0 0 0 0 1 0 1 0 0 -1 1 1 -1 1 0 -1 1 -1 1 0
1 -1 0 -1 0 -1 -1 0 0 -1 1 0 0 0 -1 1 -1 0 -1 -1 0 1
0 1 -1 0 0 -1 1 -1 -1 -1 1 0 0 0 0 -1 0 0 -1 1 0 0
1 0 0 1 0 -1 -1 0 0 0 1 -1 0 0 -1 1 -1 0 -1 -1 1 1
-1 0 -1 0 1 0 1 0 1 0 -1 -1 1 1 0 0 0 0 1 1 0 0
0 0 -1 0 0 0 1 0 1 0 0 1 -1 0 1 0 -1 1 1 -1 1 -1
1 0 0 0 -1 0 0 1 1 -1 -1 -1 0 0 -1 -1 -1 0 0 -1 1 0
1 0 1 0 1 0 0 1 0 1 1 -1 1 0 -1 0 0 0 0 -1 -1 0
0 0 -1 -1 0 0 0 -1 0 -1 1 1 0 1 -1 1 -1 -1 -1 -1 0 0
0 -1 -1 -1 1 0 0 -1 0 0 0 1 1 0 -1 1 0 0 -1 -1 0 1
0 0 1 0 -1 0 -1 0 0 1 -1 -1 0 -1 0 -1 0 -1 1 1 1 1
-1 0 0 1 1 0 -1 -1 0 -1 -1 1 -1 -1 0 0 1 0 1 1 0 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 -1 0 -1 1 0 0 1 0 0 -1
0 -1 0 -1 -1 0 0 -1 0 0 0 -1 1 1 0 1 0 0 -1 -1 0 0
-1 0 -1 -1 1 0 0 1 0 1 0 -1 1 1 1 -1 0 -1 0 0 -1 -1
-1 0 0 1 0 -1 -1 -1 0 -1 -1 1 -1 0 0 0 0 -1 1 1 1 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 1 0 0 1 0 0 1 1 1 -1
1 1 -1 0 -1 0 -1 1 0 1 -1 -1 -1 0 1 0 -1 -1 0 1 0 -1
0 -1 1 1 0 0 -1 -1 1 1 0 -1 -1 1 0 -1 1 0 -1 0 1 0
0 -1 -1 0 1 0 0 1 0 1 0 0 -1 1 0 1 1 0 -1 0 -1 -1
1 1 -1 1 -1 0 0 0 -1 1 0 0 -1 0 -1 -1 -1 0 1 1 1 1];
S = size(A)+[1,0];
B = zeros(S);
B(~eye(S)) = A;
  1 Kommentar
VBBV
VBBV am 7 Mai 2023
Verschoben: VBBV am 9 Mai 2023
Ran in:
close all; clear all; clc;
A= [0 0 0 1 0 -1 0 -1 -1 0 1 -1 0 0 1 -1 0 1 0 1 -1 0
0 1 1 1 0 0 -1 0 0 0 1 -1 1 -1 -1 1 0 -1 0 -1 1 0
-1 -1 0 0 0 0 1 0 1 0 0 -1 1 1 -1 1 0 -1 1 -1 1 0
1 -1 0 -1 0 -1 -1 0 0 -1 1 0 0 0 -1 1 -1 0 -1 -1 0 1
0 1 -1 0 0 -1 1 -1 -1 -1 1 0 0 0 0 -1 0 0 -1 1 0 0
1 0 0 1 0 -1 -1 0 0 0 1 -1 0 0 -1 1 -1 0 -1 -1 1 1
-1 0 -1 0 1 0 1 0 1 0 -1 -1 1 1 0 0 0 0 1 1 0 0
0 0 -1 0 0 0 1 0 1 0 0 1 -1 0 1 0 -1 1 1 -1 1 -1
1 0 0 0 -1 0 0 1 1 -1 -1 -1 0 0 -1 -1 -1 0 0 -1 1 0
1 0 1 0 1 0 0 1 0 1 1 -1 1 0 -1 0 0 0 0 -1 -1 0
0 0 -1 -1 0 0 0 -1 0 -1 1 1 0 1 -1 1 -1 -1 -1 -1 0 0
0 -1 -1 -1 1 0 0 -1 0 0 0 1 1 0 -1 1 0 0 -1 -1 0 1
0 0 1 0 -1 0 -1 0 0 1 -1 -1 0 -1 0 -1 0 -1 1 1 1 1
-1 0 0 1 1 0 -1 -1 0 -1 -1 1 -1 -1 0 0 1 0 1 1 0 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 -1 0 -1 1 0 0 1 0 0 -1
0 -1 0 -1 -1 0 0 -1 0 0 0 -1 1 1 0 1 0 0 -1 -1 0 0
-1 0 -1 -1 1 0 0 1 0 1 0 -1 1 1 1 -1 0 -1 0 0 -1 -1
-1 0 0 1 0 -1 -1 -1 0 -1 -1 1 -1 0 0 0 0 -1 1 1 1 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 1 0 0 1 0 0 1 1 1 -1
1 1 -1 0 -1 0 -1 1 0 1 -1 -1 -1 0 1 0 -1 -1 0 1 0 -1
0 -1 1 1 0 0 -1 -1 1 1 0 -1 -1 1 0 -1 1 0 -1 0 1 0
0 -1 -1 0 1 0 0 1 0 1 0 0 -1 1 0 1 1 0 -1 0 -1 -1
1 1 -1 1 -1 0 0 0 -1 1 0 0 -1 0 -1 -1 -1 0 1 1 1 1];
size(A)
ans = 1×2
23 22
S = size(A)+ [0 1]
S = 1×2
23 23
B = zeros(S);
B(~eye(S)) = A
B = 23×23
0 1 -1 1 0 1 -1 0 -1 0 -1 -1 1 0 0 -1 0 0 0 -1 -1 1 0 0 0 1 -1 1 -1 0 -1 1 0 -1 -1 -1 1 1 -1 -1 -1 0 -1 1 0 0 0 0 0 -1 0 0 0 -1 -1 0 0 0 1 0 0 -1 0 -1 1 1 -1 0 1 -1 1 0 0 1 1 0 -1 -1 0 1 0 0 -1 -1 -1 1 0 0 1 1 1 0 1 -1 1 1 0 -1 0 -1 1 0 -1 0 -1 -1 -1 0 1 -1 0 0 -1 0 1 0 -1 0 1 0 0 0 0 -1 0 -1 -1 -1 1 0 0 -1 0 -1 0 -1 1 0 1 1 0 0 0 -1 0 0 1 1 1 0 1 1 1 -1 0 0 0 -1 -1 1 -1 -1 0 -1 -1 0 0 0 0 0 0 1 -1 0 -1 1 0 1 1 -1 -1 -1 -1 0 0 0 0 0 0 0 -1 -1 0 -1 1 0 -1 1 0 1 1 0 0 1 -1 0 0 1 0 -1 1 0 -1 1 0 -1 0 1 0 -1 -1 0 0 -1 0 0 1 1 0 0

Melden Sie sich an, um zu kommentieren.

Melden Sie sich an, um diese Frage zu beantworten.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 7 Mai 2023
Ran in:
Your A is 23 x 22. You add 1 row and 0 columns to that to get B of size 24 x 22.
A= [0 0 0 1 0 -1 0 -1 -1 0 1 -1 0 0 1 -1 0 1 0 1 -1 0
0 1 1 1 0 0 -1 0 0 0 1 -1 1 -1 -1 1 0 -1 0 -1 1 0
-1 -1 0 0 0 0 1 0 1 0 0 -1 1 1 -1 1 0 -1 1 -1 1 0
1 -1 0 -1 0 -1 -1 0 0 -1 1 0 0 0 -1 1 -1 0 -1 -1 0 1
0 1 -1 0 0 -1 1 -1 -1 -1 1 0 0 0 0 -1 0 0 -1 1 0 0
1 0 0 1 0 -1 -1 0 0 0 1 -1 0 0 -1 1 -1 0 -1 -1 1 1
-1 0 -1 0 1 0 1 0 1 0 -1 -1 1 1 0 0 0 0 1 1 0 0
0 0 -1 0 0 0 1 0 1 0 0 1 -1 0 1 0 -1 1 1 -1 1 -1
1 0 0 0 -1 0 0 1 1 -1 -1 -1 0 0 -1 -1 -1 0 0 -1 1 0
1 0 1 0 1 0 0 1 0 1 1 -1 1 0 -1 0 0 0 0 -1 -1 0
0 0 -1 -1 0 0 0 -1 0 -1 1 1 0 1 -1 1 -1 -1 -1 -1 0 0
0 -1 -1 -1 1 0 0 -1 0 0 0 1 1 0 -1 1 0 0 -1 -1 0 1
0 0 1 0 -1 0 -1 0 0 1 -1 -1 0 -1 0 -1 0 -1 1 1 1 1
-1 0 0 1 1 0 -1 -1 0 -1 -1 1 -1 -1 0 0 1 0 1 1 0 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 -1 0 -1 1 0 0 1 0 0 -1
0 -1 0 -1 -1 0 0 -1 0 0 0 -1 1 1 0 1 0 0 -1 -1 0 0
-1 0 -1 -1 1 0 0 1 0 1 0 -1 1 1 1 -1 0 -1 0 0 -1 -1
-1 0 0 1 0 -1 -1 -1 0 -1 -1 1 -1 0 0 0 0 -1 1 1 1 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 1 0 0 1 0 0 1 1 1 -1
1 1 -1 0 -1 0 -1 1 0 1 -1 -1 -1 0 1 0 -1 -1 0 1 0 -1
0 -1 1 1 0 0 -1 -1 1 1 0 -1 -1 1 0 -1 1 0 -1 0 1 0
0 -1 -1 0 1 0 0 1 0 1 0 0 -1 1 0 1 1 0 -1 0 -1 -1
1 1 -1 1 -1 0 0 0 -1 1 0 0 -1 0 -1 -1 -1 0 1 1 1 1];
S = size(A)+[0,1];
B = zeros(S);
B(~eye(S)) = A;
B
B = 23×23
0 1 -1 1 0 1 -1 0 -1 0 -1 -1 1 0 0 -1 0 0 0 -1 -1 1 0 0 0 1 -1 1 -1 0 -1 1 0 -1 -1 -1 1 1 -1 -1 -1 0 -1 1 0 0 0 0 0 -1 0 0 0 -1 -1 0 0 0 1 0 0 -1 0 -1 1 1 -1 0 1 -1 1 0 0 1 1 0 -1 -1 0 1 0 0 -1 -1 -1 1 0 0 1 1 1 0 1 -1 1 1 0 -1 0 -1 1 0 -1 0 -1 -1 -1 0 1 -1 0 0 -1 0 1 0 -1 0 1 0 0 0 0 -1 0 -1 -1 -1 1 0 0 -1 0 -1 0 -1 1 0 1 1 0 0 0 -1 0 0 1 1 1 0 1 1 1 -1 0 0 0 -1 -1 1 -1 -1 0 -1 -1 0 0 0 0 0 0 1 -1 0 -1 1 0 1 1 -1 -1 -1 -1 0 0 0 0 0 0 0 -1 -1 0 -1 1 0 -1 1 0 1 1 0 0 1 -1 0 0 1 0 -1 1 0 -1 1 0 -1 0 1 0 -1 -1 0 0 -1 0 0 1 1 0 0

Weitere Antworten (0)

Kategorien

Mehr zu Operating on Diagonal Matrices finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by