ODE45 for Equations of Motion

7 Ansichten (letzte 30 Tage)
Sam Butler
Sam Butler am 21 Mär. 2023
Kommentiert: Shree Charan am 4 Mai 2023
Hi, I am hoping someone can help me with the following issue. I have tried this problem multiple times and still can't seem to write the correct code (I am new to MATLAB).
The following three equations of motion are to be solved:
theta dot out is the input velocity into the system, it is time dependant and is characterised by the equation:
All other variables are constant (e.g. theta_dot_zero,J1,c1,k1,f (this is not frequency) etc.).
I believe you can use ode45 to solve this however I have had no luck.
Initial conditions can be taken as zero, a timespan of 0-20seconds can be used as an example.
The aim is to then plot velocity, acceleration and displacement graphs for the unknown theta variables of subscript 1,2,n and out.
I hope someone can help with this! I would really appreciate a draft of some code.
Thanks!
  8 Kommentare
Torsten
Torsten am 22 Mär. 2023
Bearbeitet: Torsten am 22 Mär. 2023
Do you see the problem why the integration takes so long and is almost impossible to perform ?
param.vin = 600*(2*pi/60); %% 600 is the input velocity in rpm
param.f_mech = param.vin/(2*pi);
theta_out_dot = @(t)param.vin+(0.02*param.vin*cos(72*pi*param.f_mech*t))+(0.005*param.vin*cos(144*pi*param.f_mech*t));
t=0:0.000001:0.1;
plot(t,theta_out_dot(t))
Shree Charan
Shree Charan am 4 Mai 2023
@Sam Butler In the question you mention that "theta_dot_out" is the input velocity into the system and "theta_dot_zero" is a constant.
However in the line
theta_out_dot = param.vin+(0.02*param.vin*cos(72*pi*param.f_mech*t))+(0.005*param.vin*cos(144*pi*param.f_mech*t));
theta_dot_zero is replaced with vin which is the input velocity.
Can you please clarify if theta_out_dot = vin as mentioned in the question or if theta_dot_zero = vin.

Melden Sie sich an, um zu kommentieren.

Antworten (0)

Kategorien

Mehr zu Programming finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by