How to implement a function within another one ?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Martin Matin
am 18 Mär. 2015
Kommentiert: Martin Matin
am 20 Mär. 2015
Hi, I'd like to use the bisection method to find the root of a function "Fetoile" The method works but I have to iterate it for some values of a parameter "i". The problem is, the bisection function does not use "i".
Here is the code that gives me the results for "Fetoile" :
function Fetoile = q4(v)
% datas
vitesse_rotation= [83.7758040957278, 119.587013890941, 155.398223686155, 191.209433481369, 227.020643276582, 262.831853071796, 298.643062867009, 334.454272662223, 370.265482457437, 406.07669225265, 441.887902047864, 477.699111843078, 513.510321638291, 549.321531433505, 585.132741228718, 620.943951023932, 656.755160819146, 692.566370614359, 728.377580409573, 764.188790204786]
couple=[206.41064280052, 243.796265372056, 256.741969803922, 258.849308707433, 255.11836152428, 247.801181783381, 238.039957653591, 226.445249315901, 213.320493034029, 198.699623003111, 181.889713594511, 163.718280099678, 145.175662563345, 126.558747418095, 108.009552378088, 89.6025609484197, 71.3773301900352, 53.3538548851947, 35.5406860579882, 17.9395273160688]
rho=1.2;
S=2.28;
Cx=0.31;
mveh=1360;
g=9.81;
f0=0.0136;
f2=4.*10.^(-7);
ntrans=0.92;
atrans=1.04;
btrans=0.0025;
R=0.31;
i=[9.62,5.87,3.91,2.90,2.31];
teta=0;
%end of datas
for m = 1:5
Cmax=spline(vitesse_rotation,couple,i(m).*(v)/R);
Faero = (1/2)*rho*S*Cx*(v).^2;
Frlt = mveh*g*cos(teta)*(f0+f2*(v).^2);
Fgrav = mveh*g*sin(teta);
Fmotmax = ntrans*(i(m)/R)*Cmax;
Fetoile = Faero + Frlt + Fgrav - Fmotmax;
tabFetoile(m) = Fetoile;
end %end of for loop
disp('The results are :');
disp(tabFetoile);
And here is the code for the bisection, I tried a loop on the values of "vmin" are values that I'm sure are negatives.
function root = bishoz(f,vmin,vmax)
resultat = [];
for m = 1:5
vmin=[6,9.5,13.5,16.5,19];
vmax = 150;
fvmin(m) = f(vmin(m));
fvmax = f(vmax);
if fvmax*fvmin(m) > 0
disp('Valeurs de même signe.');
else
root = (vmax + vmin(m))/2;
err = abs(f(root));
end
while err > 1e-7
if fvmax*f(root)<0
vmin(m) = root;
else
vmax = root;
end %end of if
root = (vmax + vmin(m))/2;
err = abs(f(root));
end %end of while loop
resultat(m)=root;
end %end of for loop
disp(resultat);
0 Kommentare
Akzeptierte Antwort
John
am 18 Mär. 2015
I read through your example and it looks like the language functionality you are looking for are nested functions. Please see this for more info http://www.mathworks.com/help/matlab/matlab_prog/nested-functions.html
3 Kommentare
John
am 19 Mär. 2015
I do not understand what you are looking for Martin. Are you having problems calling the nested function from the outer main function?
It would help if you could provide a simple code example. That would help greatly. I have a feeling the answer you are looking for is close to hand. So please help us with a small example.
Weitere Antworten (1)
Xia
am 18 Mär. 2015
Sorry I read your code twice but got lost. Would you please epitomize your question by a simple example? Maybe it'll be a little better for other guys to get into this question..
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!