Using the fields of a structure to index through a vector and generate a resulting structure
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Scorp
am 27 Sep. 2022
Kommentiert: Scorp
am 27 Sep. 2022
dataArray = [21,22,23,24,25,26,27,28,29,30];
structureOfIndexes.a1 = [2,5,8];
structureOfIndexes.a2 = [3,4];
structureOfIndexes.a3 = [1,2,3,5,9];
% How do I use the structure of indexes to generate the 'resultStructure'(seen below)
resultStructure.a1 = [22,25,28];
resultStructure.a2 = [23,24];
resultStructure.a3 = [21,22,23,25,29];
% without using a for-loop to index through a1,a2,a3
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Eric Delgado
am 27 Sep. 2022
dataArray = [21,22,23,24,25,26,27,28,29,30];
structureOfIndexes.a1 = [2,5,8];
structureOfIndexes.a2 = [3,4];
structureOfIndexes.a3 = [1,2,3,5,9];
resultStructure = structfun(@(x) dataArray(x), structureOfIndexes, "UniformOutput", false)
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