Dimension mismatch - saving output from a for loop

2 Ansichten (letzte 30 Tage)
Bran
Bran am 17 Feb. 2015
Bearbeitet: per isakson am 17 Feb. 2015
Just a straight forward question;
I am running a basic for loop;
TT = length of some vector;
for i = 2:TT
SS = Section1X(yy(i-1):yy(i));
AB =find(SS<=(0.9664*9.81*0.95));
if numel(AB)>0
NEW(i)=yy(i-1);
end
end
I want to store the values of AB on each loop and when I changed the code to AB(i,:) = find(SS..etc.) I get a dimension mismatch error.

Antworten (2)

per isakson
per isakson am 17 Feb. 2015
Bearbeitet: per isakson am 17 Feb. 2015
The problem might be that find returns vectors, the length of which varies with i
Repolace
AB(i,:) = find(SS..etc.)
by
AB{i,:} = find(SS..etc.)
Another approach
dbstop if error
and inspect the variables involved
  2 Kommentare
per isakson
per isakson am 17 Feb. 2015
Bearbeitet: per isakson am 17 Feb. 2015
Copied to here by per isakson
I get the following error from this approach
??? Cell contents assignment to a non-cell array object.
Error in ==> METRICSFINAL2 at 177
AB{i,:} =find(SS<=(0.9664*9.81*0.95));
per isakson
per isakson am 17 Feb. 2015
Bearbeitet: per isakson am 17 Feb. 2015
My mistake. Should read
AB{i} =find(SS<=(0.9664*9.81*0.95));

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Bran
Bran am 17 Feb. 2015
I get the following error from this approach
??? Cell contents assignment to a non-cell array object.
Error in ==> METRICSFINAL2 at 177
AB{i,:} =find(SS<=(0.9664*9.81*0.95));

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