Regexp to match floating numbers and ignore scientific notation numbers

I hava a script to extract one value from each line of a text file.

All the lines are in this sort:

5603 1 1 1 1 115 1 17 1 1 1.00212E-17 0.00528

I need to extract only the last value, which in this line is: 0.00528.

How can I organize the Regexp expression to only pull these type of values?

Thanks!

[Stephen23]

"How can I organize the Regexp expression to only pull these type of values?"

Is there a particular reason why you need to use regular expressions? If that data is imported from a file, it would probably be simpler to only import that column when importing. Or, unless the files really are very large, simply import all columns and then pick the ones you want.

Please upload a sample file by clicking the paperclip button.

[Thamer Albagami]

The file is too large and doesn't have the same format of lines. The data are organzied in unstrcutued format, like:

Data1 = [

1 1 1 1 1 1 1 1 1 1 8.02709E-20 0.05846

. . . . . . . . . . . .

. . . . . . . . . . . .

] ;

HData1X = [

-1.07100E+01 1.07100E+01 0.00000E+00

];

HData1Y = [

-1.07100E+01 1.07100E+01 0.00000E+00

];

So, I managed to pull the lines I need and ignore the others. I only need the correct format of Regexp to pull the value of interest, which is a float with 5 significant difits from the lines that are like:

1 1 1 1 1 1 1 1 1 1 8.02709E-20 0.05846

thanks!

[Stephen23]

If you have already isolated that line and the value you want is always the last one, then a simple and efficient approach would be to SCCANF the entire line and use indexing to obtain the last value:

str = '603    1    1    1    1  115    1   17    1    1  1.00212E-17 0.00528';
vec = sscanf(str,'%f');
num = vec(end)

num = 0.0053

Answer 1

[Walter Roberson]

\d+\.\d{5}\>