How to check if there are more ones than zeros in the variable.

For example, if there is the variable x;
x = [1 1 1 1 1 1 1 1 0 0 0];
How to check if it has ones than zeros?

1 Kommentar

if the verctor only contains 1s and 0s, you can just do a sum divided by length of the vector

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 Akzeptierte Antwort

x = [1 1 1 1 1 1 1 1 0 0 0]
x = 1×11
1 1 1 1 1 1 1 1 0 0 0
has_more_ones = mean(x) > 0.5 %note that exactly equal does not qualify as "more"
has_more_ones = logical
1

Weitere Antworten (1)

Another way (assuming only 1s and 0s in the array):
moreOnes = nnz(x) > numel(x)/2

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