Hi
I want to save results of calculation in an emty struct(3*3*2 with fields:cost)named "mymax".
"stwhole" (3*3*2 with field:cost) at the following code is the name of my original struct. in each field of stwhole that is named cost are two values. and I want to multiply them (these two values of each field) to elements of matrix A separately then find the max of them and save it to corresponding fields in struct "mymax". the size of matrix A is 1*9.
this code doesn't work correctly.
PLEASE HELP ME
if true
empty_max.cost=[]
mymax=repmat(empty_max,[3,3,2])
for iteration:1:9
for k=1:9
mymax(k).cost=[]
for i=1:3
for j=1:3
for m=1:2
ops=(stwhole(i,j,m).cost).*A(K)
ty=max(ops)
mymax(k).cost=[ty]
end
end
end
end
end

9 Kommentare

Sara
Sara am 13 Jan. 2015
DO you get an error from matlab or is the result wrong?
fatema saba
fatema saba am 13 Jan. 2015
NO of course with little changes (omit iteration and also substitute A with 2)the code gives me a struct that just one filed of 18 fields is filled by result.
I can't save results in new struct. only one field is filled by result.
Sara
Sara am 13 Jan. 2015
On this line you define mymax as a 3,3,2 matrix
mymax=repmat(empty_max,[3,3,2])
but then you treat it as array by doing
mymax(k)
What is the desired outcome?
fatema saba
fatema saba am 13 Jan. 2015
I want to any field of mymax fill with corresponding "ty" that is maximum of product of multiplying two values of each field of stwhole to element of A (or if you think simple substitute A with 2).
fatema saba
fatema saba am 13 Jan. 2015
Bearbeitet: fatema saba am 13 Jan. 2015
for example imagine that
stwhole (1,2,1).cost= 2 3
I do 2*2=4 and 2*3=6
them max(4 and 6)is 6
then I save it to mymax(1,2,1)
or
stwhole (2,2,2).cost= 4 5
I do 2*4=8 and 2*5=10
them max(8 and 10)is 10
then I save 10 to mymax(2,2,2)
Sara
Sara am 13 Jan. 2015
Bearbeitet: Sara am 13 Jan. 2015
At any k-iteration you overwrite mymax though. you may want to change:
mymax(k).cost=[ty]
into
mymax(i,j,m,k).cost=ty
or
mymax(i,j,m).cost=max(ty,mymax(i,j,m).cost)
It really depends on what you're trying to achieve when you have an A matrix. Which one is the one you need? Some additional changes are needed depending on which case you meant to implement.
fatema saba
fatema saba am 13 Jan. 2015
excuse me I change my code but it is something wrong yet
if true
for k=1:9
mymax(k).cost=[]
for i=1:3
for j=1:3
for m=1:2
ops=(stwhole(i,j,m).cost).*A(k)
ty=max(ops)
mymax(i,j,m,k).cost=ty
end
end
end
end
end
Sara
Sara am 13 Jan. 2015
You will need to change also the initialization into
mymax=repmat(empty_max,[3,3,2,9])
and remove the line
mymax(k).cost=[]
fatema saba
fatema saba am 13 Jan. 2015
A is 1*9 matrix I want to on each iteration one element of A multiply to stwhole(I,j,m) and max of this product save in mymax. then at the next iteration the second lement of A repeat this process and results save in mymax. and these iterations continue up to the end element of A.

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 Akzeptierte Antwort

Sara
Sara am 13 Jan. 2015

0 Stimmen

Here is how your code will look like:
if true
empty_max.cost=[]
mymax=repmat(empty_max,[3,3,2,numel(A)])
for k=1:numel(A)
for i=1:3
for j=1:3
for m=1:2
mymax(i,j,m,k).cost=max(stwhole(i,j,m).cost*A(k))
end
end
end
end
end

1 Kommentar

fatema saba
fatema saba am 13 Jan. 2015
Thank you SARA. you help me a lot.
thanks for your kindness.

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