Converge a 1x30 row vector to a 3x10 matrix
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Wietze Zijpp
am 5 Apr. 2022
Kommentiert: Voss
am 6 Apr. 2022
Suppose I have the following
z = [1:30]
Now I want to create a 3x 10 matrix. Where the entries in the first row are the first 10 values. In the second row entries 11:20 and in the third row 21:30
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Wietze Zijpp
am 5 Apr. 2022
Bearbeitet: Torsten
am 5 Apr. 2022
1 Kommentar
Voss
am 6 Apr. 2022
"the entries in the first row are the first 10 values. In the second row entries 11:20 and in the third row 21:30"
If you want the order like that, you have to do it differently:
z = 1:30;
mymat = reshape(z,3,10)
mymat = reshape(z,10,3).'
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