As I understand, the exist() function in MATLAB will return "2" if the input is a MATLAB function.
The list of options for the second input 'kind' are builtin, class, dir, file, and var.
I want to input 'kind' so that exist() will ONLY search for functions, and return 2 if it is a match to a function and a 0 if not.
Is there any way to do this?

2 Kommentare

Sean de Wolski
Sean de Wolski am 22 Dez. 2014
So you mean ONLY functions or any MATLAB files that will run (scripts/functions/classes)? which will return something for scripts and classes as well.
Sean de Wolski
Sean de Wolski am 22 Dez. 2014
For functions only, this blog post and ensuing comments explains:

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

matt dash
matt dash am 19 Dez. 2014

2 Stimmen

An option that is not exactly what you describe, but might work for you:
isempty(which([functionname,'.m']))

5 Kommentare

per isakson
per isakson am 20 Dez. 2014
... but why not just
isempty(which( functionname ))
matt dash
matt dash am 20 Dez. 2014
Without the .m it will not distinguish between functions and variables.
per isakson
per isakson am 20 Dez. 2014
Bearbeitet: per isakson am 20 Dez. 2014
Yes, exactly!
Daniel
Daniel am 22 Dez. 2014
Will this work in a deployed application? since the file isn't actually on the filepath any longer as its packaged in an EXE?
Sean de Wolski
Sean de Wolski am 22 Dez. 2014
What about p-files?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Azzi Abdelmalek
Azzi Abdelmalek am 19 Dez. 2014
Bearbeitet: Azzi Abdelmalek am 19 Dez. 2014

0 Stimmen

exist()==2
%or
A = exist('name','file')

1 Kommentar

Daniel
Daniel am 19 Dez. 2014
My problem here is what if it exists as a workspace variable or another non-m file on the search path? in that case it will return 1 or 5 respectively, while I would still not be sure if it exists as a funciton.

Melden Sie sich an, um zu kommentieren.

Kategorien

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by