Nth term of a Leibniz Series

I'm trying to create a function that will take a signle input (N) and output the Nth term in the Leibniz Series but for some reason my code keeps failing to pass these test: First term check, Check random variable.

Here is my function and how i am calling it.

test = LeibnizTerm(7)

function y = LeibnizTerm(N)
y = (-1)^N/(2*N+1);
end

Answer 1

[Voss]

It depends on if the first term should correspond to input N == 0 or input N == 1. If it's N == 0, I think it's ok how you have it.

LeibnizTerm(0)

ans = 1

LeibnizTerm(1)

ans = -0.3333

LeibnizTerm(2)

ans = 0.2000

If it should start with N == 1, then you have to make a couple of adjustments (see modified function LeibnizTerm1 below).

LeibnizTerm1(1)

ans = 1

LeibnizTerm1(2)

ans = -0.3333

LeibnizTerm1(3)

ans = 0.2000

function y = LeibnizTerm(N)
y = (-1)^N/(2*N+1);
end

function y = LeibnizTerm1(N)
y = (-1)^(N+1)/(2*N-1);
end

Answer 2

[Onimisi]

n=0:19
x=(1)*1./((2*n)+1)
y=x.*(-1).^n
LeibnizTerms=y

Answer 3

[Onimisi]

n=0:19

n = 1×20

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19

x=(1)*1./((2*n)+1)

x = 1×20

1.0000 0.3333 0.2000 0.1429 0.1111 0.0909 0.0769 0.0667 0.0588 0.0526 0.0476 0.0435 0.0400 0.0370 0.0345 0.0323 0.0303 0.0286 0.0270 0.0256

y=x.*(-1).^n

y = 1×20

1.0000 -0.3333 0.2000 -0.1429 0.1111 -0.0909 0.0769 -0.0667 0.0588 -0.0526 0.0476 -0.0435 0.0400 -0.0370 0.0345 -0.0323 0.0303 -0.0286 0.0270 -0.0256

LeibnizTerms=y

LeibnizTerms = 1×20

1.0000 -0.3333 0.2000 -0.1429 0.1111 -0.0909 0.0769 -0.0667 0.0588 -0.0526 0.0476 -0.0435 0.0400 -0.0370 0.0345 -0.0323 0.0303 -0.0286 0.0270 -0.0256