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HighPhi
HighPhi am 9 Feb. 2022

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u = [1, 1; ...
2, 2; ...
3, 3];
uInverse = flip(u)
uInverse = 3×2
3 3 2 2 1 1
u = [1, 1; ...
2, 2; ...
3, 3];
u90 = rot90(u)
u90 = 2×3
1 2 3 1 2 3
u_neg90 = rot90(u, 3)
u_neg90 = 2×3
3 2 1 3 2 1

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DGM
DGM am 9 Feb. 2022
Bearbeitet: DGM am 9 Feb. 2022
Using an asymmetric input allows some distinctions to be made. If the OP is trying to do linear algebra, transposition is probably what's intended.
u = [1, 4; ...
2, 5; ...
3, 6];
u_90 = rot90(u) % rotate 90
u_90 = 2×3
4 5 6 1 2 3
u_neg90 = rot90(u, 3) % rotate -90 (or 270)
u_neg90 = 2×3
3 2 1 6 5 4
u_tpose = u.' % transpose
u_tpose = 2×3
1 2 3 4 5 6
Note that transposition is a special case of permutation that only applies to 2D arrays. More generally, you can do:
u_tpose = permute(u,[2 1])
u_tpose = 2×3
1 2 3 4 5 6

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