Decompressing *.7Z Files with MATLAB
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I have a 7z file. I wish to decompress it using Matlab. How can I do this? The inbuilt matlab functions dont support it.
I have tried,
[status,result] = system(['"C:\Program Files\WinRAR\UnRAR.exe" e ' E:\myFile.7z ' >null']);
however this fails as it gives
result =
UNRAR 5.11 freeware Copyright (c) 1993-2014 Alexander Roshal
E:\myFile.7z is not RAR archive
No files to extract
On closer inspection unrar.exe is not the same as winrar (which can do 7z). Hence i download 7-zip
[status,result] = system(['"C:\Program Files\7-Zip\7z.exe" e ' E:\myFile.7z]);
result =
7-Zip [64] 9.20 Copyright (c) 1999-2010 Igor Pavlov 2010-11-18
Processing archive: E:\myFile.7z
Error: Can not open file as archive
any ideas?
thanks
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Weitere Antworten (1)
Jake August
am 19 Apr. 2016
This was very helpful. Someone else looking might find this useful.
% for 7zip 15.14 x64
file7z = 'D:\my.7z';
% rest of code
[dir7z,~,~] = fileparts( file7z );
dir7z = ['"' dir7z '"'];
file7z = ['"' file7z '"'];
[status,cmdout] = system( ['"C:\Program Files\7-Zip\7z.exe" x -o',dir7z,' ',file7z] );
3 Kommentare
ZHIWEI WANG
am 11 Jun. 2021
It works well!
Verena Schwachmeyer
am 13 Jun. 2022
Hi Jake August,
thank you. Your solution works for me - but only if I run it once. When this operation is part of an iteration, Matlab freezes during the second loop. Do you have an idea why that is and how to fix it?
-Verena
Walter Roberson
am 13 Jun. 2022
Perhaps using .NET Systems.Diagnostic.Process() to start the process instead of system()
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