if the imaginary part of a complex number is zero
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Hello
Here is my code where I want to see if the imaginary part of a number is zero then int=int+1; however, the imaginary part is not considered as zero though using the command by matlab documentation. what should i do?
int=0
F = @(z)((z-20.6667)^2+((-0.5*(z-10))-14.6667)^2-18.1353^2);
opts = optimoptions('fsolve', 'Display', 'off');
z(1) = fsolve(@(z) F(z), 1+1i, opts);
w(1)=-0.5*(z(1)-10);
z(2)=fsolve(@(z) F(z), 30+1i,opts);
w(2)=-0.5*(z(2)-10);
for v=1:2
tt(v)=~any(imag(z(v)));
if (z(v)>10) && (z(v)<=20 || abs(z(v)-20)<1e-6 )&& tt(v)==1
if v==2 && abs(z(1)-z(2))<1e-6
int;
else
int=int+1;
Points(int,:)=[z(v) w(v)];
end
end
end
tt(v) must be 1 for both roots of the equation.
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Antworten (1)
Gargi Patil
am 12 Nov. 2021
Hi,
My understanding is that you would like to detect imaginary values equal to zero at the following line:
tt(v)=~any(imag(z(v)));
However, upon closest inspecting the imaginary values of z, they are not exactly zero. For example, the imaginary value of z(1) is 0.000000002392847.
nearestDecimalDigit = 4; %set the number of digits as required
tt(v)=~any(round(imag(z(v)), nearestDecimalDigit)); %round to the nearest 4 decimal digits
This sets both the values of tt as 1.
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