Group values in a double & create new matrix according to the groups formed

I have a double variable A with 1 column and 30000 rows:

A=[44
12
79
12
83
63
53…]

I applied the following code:

groupA=cell2mat(A(:,1));
[~, ~, ugroupA] = unique(groupA)
DA=dummyvar(ugroupA);

And I obtained a double matrix with 30000 rows and 262 columns with ones and zeros. The number of columns -262 - reflects the different numbers of the variable A.

What I am trying to do now is to apply basically the same code, but instead of getting a new column of ones and zeros for each different number in A, I would like to have a different column for the values between:

0 to 5
5 to 10
10 to 15
15 to 20
20 to 30
30 to 40
40 to 50
50 to 100
100 to 150
150 to 200
200 to 300

So instead of obtaining a new variable DA with 30000 rows and 262 columns, I would get a variable with 30000 rows but 11 columns.

Can someone help me please? Thank you

Answer 1

[Kelly Kearney]

xedge = [0 5 10 15 20 30 40 50 100 150 200 300];
A = rand(1000,1)*300;
[n, idx] = histc(A, xedge);
isin = bsxfun(@eq, idx, 1:length(xedge)-1);

Not entirely sure what your dummyvar was, but I think this gets to the 1/0 matrix you wanted.

Answer 2

[Andrei Bobrov]

EDIT

v = [0 
5 
10 
15 
20 
30 
40 
50 
100 
150 
200
inf];
[~,b] = histc(A,v);
out = dummyvar(b);

[Maria]

It gives this error:

Error using histc First Input must be a real non-sparse numeric array.

[Maria]

I introduced cell2mat and it solved this error, but then when I do

out = dummyvar(b);

I get another error:

 Error using dummyvar (line 85)
 Each element of GROUP must be a positive integer.

[Andrei Bobrov]

corrected