# HOW TO ENCODE AN 8BIT VALUE FROM A MATRIX

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Abirami am 14 Aug. 2014
Bearbeitet: Abirami am 15 Aug. 2014
HELLO
I have generated a 256x256 matrix with an 8bit binary sequence present in each element. I wish to encode the sequence using the following scheme
A=00
B=01
C=10
D=11
clc
clear all
close all
imshow(a)
disp(a)
for i=1:1:256
for j=1:1:256
b{i,j,1} = dec2bin(a(i,j),8);
end
end
disp(b)
M=randint(256,256,[0,256]);
disp(M)
for k=1:1:256
for l=1:1:256
N{k,l,1} = dec2bin(M(k,l),8);
end
end
disp(N)
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### Akzeptierte Antwort

Pratik Bajaria am 14 Aug. 2014
Hello, Check this. I think it would work for you. It worked for me fine.
for i=1:size(b,1)
for j=1:size(b,2)
dum=0;
for k=1:2:size(b,3)
dum=dum+1;
if (b(i,j,k)*10+b(i,j,k+1))==00
test(i,j,dum)='A';
elseif (b(i,j,k)*10+b(i,j,k+1))==01
test(i,j,dum)='B';
elseif (b(i,j,k)*10+b(i,j,k+1))==10
test(i,j,dum)='C';
else
test(i,j,dum)='D';
end
end
end
end
Please let me know in case of further doubts.
Regards, Pratik
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Pratik Bajaria am 14 Aug. 2014
Ok Let me use altogether new concept to get it done. Used a lot of times in C/C++, the idea of structures.
So use the following code, once you are done executing the above code, I posted and converted them to a 256x256x4 Char Matrix.
for i=1:size(b,1)
for j=1:size(b,2)
test_encode_dummy=test(i,j,1);
for k=2:size(test,3)
test_encode_dummy=cat(2,test_encode_dummy,test(i,j,k));
end
test_encode(i,j).code=test_encode_dummy;
end
end
That's it!
Hope it helps.
Regards, Pratik
Abirami am 15 Aug. 2014
Bearbeitet: Abirami am 15 Aug. 2014
sir, im not able to follow...i tried but im getting the following error
Attempted to access b(1,1,2); index out of bounds because size(b)=[256,2048,1].
Error in ==> prat1 at 20 if (b(k,l,m)* 10+b(k,l,m+1))==00
also im not able to view the result...pls help..thanks in advance

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### Weitere Antworten (1)

David Sanchez am 14 Aug. 2014
M=randint(256,256,[0,256]);
disp(N)
N=zeros(size(M));
for k=1:256
for l=1:256
N(k,l) = str2double(dec2bin(M(k,l),8));
end
end
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