一个方程式如何求tan(theta/2)

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毅 字
毅 字 on 22 Sep 2021
Answered: 毅 王 on 22 Sep 2021
clear;clc;
syms xc yc x y L alpha theta rho1 rho2 K1 K2 tau
tau = (L*(2*K2*rho1^2*sin(theta)-K1*(L^2-rho1^2-rho2^2)*sin(theta)-K1*(2*(rho1^2*rho2^2+rho1^2*L^2+rho2^2*L^2)-rho1^4-rho2^4-L^4)^0.5*cos(theta)))/(2*rho1)
如何表达出tan(theta/2)

Answers (1)

毅 王
毅 王 on 22 Sep 2021
tan2θ=2tanθ/(1-tan^2(θ)) =-2根号2

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