Problem in solving a set of 5 odes and getting Nan values

4 Ansichten (letzte 30 Tage)
Dear All,
I am trying to solve a set of 5 ode equaions using ode45 solver by using a separate independent function (named "Multi_func" contains my equations. However, they are solved with NaN values in final "eq" matrix.
any help is appreciated.
%%%%% Parameters
Q=[1100 350 1240 930 3620];
V_i=[3180 1696 1065 27000 2670];
V_t=[2290 1610 300 26649 0 ];
k_el=[0 0 90 0 0];
g=0;
tpan=[0 1];
Vm=[0 1.19e-4 2e-5 0 0];
K_M=[0 27 32 0 0];
W=6;
initial_conditions=zeros(1,W-1);
initial_conditions(5)=10; % ug/ml
[t,eqs]=ode45(@(t,eqs) Multi_func(t,eqs,Q,V_i,k_el,V_t,Vm,K_M,g,W),tpan,initial_conditions);
Time2=t./60; %convert to hr
cc=jet(W);
for i=1:W-1
plot(Time2,eqs(:,i),'color', cc(i,:));
hold on
end
my Multi_func function is:
function eq = Multi_func(t,eqs,Q,V_i,k_el,V_t,Vm,K_M,g,W)
eq=zeros(W-1,1);
eq(1)=((Q(1)*eqs(5)-Q(1)*eqs(1))/V_i(1))-(k_el(1)*eqs(5)/V_i(1))-V_t(1)*(((Vm(1)*eqs(1)))/(K_M(1)+eqs(1)))/V_i(1);
eq(2)=((Q(2)*eqs(5)-Q(2)*eqs(2))/V_i(2))+(Q(1)*eqs(1)/V_i(2))-(k_el(2)*eqs(5)/V_i(2))-V_t(2)*(((Vm(2)*eqs(2)))/(K_M(2)+eqs(2)))/V_i(2);
eq(3)=((Q(3)*eqs(5)-Q(3)*eqs(3))/V_i(3))-(k_el(3)*eqs(5)/V_i(3))-V_t(3)*(((Vm(3)*eqs(3)))/(K_M(3)+eqs(3)))/V_i(3);
eq(4)=((Q(4)*eqs(5)-Q(4)*eqs(4))/V_i(4))-(k_el(4)*eqs(5)/V_i(4))-V_t(4)*(((Vm(4)*eqs(4)))/(K_M(4)+eqs(4)))/V_i(4);
eq(5)=(Q(1)*eqs(1)+Q(2)*eqs(2)+Q(3)*eqs(3)+Q(4)*eqs(4)-Q(5)*eqs(5))/V_i(5)+V_t(5)*(((Vm(5)*eqs(5)))/(K_M(5)+eqs(5)))/V_i(5)+g/V_i(5);
end

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 15 Sep. 2021
K_M=[0 27 32 0 0];
First K_M is 0.
W=6;
initial_conditions=zeros(1,W-1);
initial_conditions(5)=10; % ug/ml
First boundary condition is 0
eq(1)=((Q(1)*eqs(5)-Q(1)*eqs(1))/V_i(1))-(k_el(1)*eqs(5)/V_i(1))-V_t(1)*(((Vm(1)*eqs(1)))/(K_M(1)+eqs(1)))/V_i(1); ^^^^^^^^^^^^^^^^
Notice the /(K_M(1)+eqs(1)) . As pointed out above, K_M(1) is 0 an eqs(1) starts out 0, and sum of those two is 0, so you have a division by 0 there.
  3 Kommentare
Walter Roberson
Walter Roberson am 15 Sep. 2021
Vm(1) is also zero. It shuld be able to cross off the (((Vm(1)*eqs(1)))/(K_M(1)+eqs(1)))/V_i(1).
Try it.
(5*0)/0
ans = NaN
5*(0/0)
ans = NaN
(0*5)/0
ans = NaN
0*(5/0)
ans = NaN
(0/0)*5
ans = NaN
0/0*0
ans = NaN
5*sin(0)/0
ans = NaN
syms x real
expr = 5*(sin(x)/x)
expr = 
limit(expr, x, 0, 'left')
ans = 
5
limit(expr, x, 0, 'right')
ans = 
5
5 * x / x
ans = 
5
That is, you can talk about limits, but the symbolic engine does not automatically calculate in terms of limits.
Ghs Jahanmir
Ghs Jahanmir am 15 Sep. 2021
Yes, I got the point.
Thanks a lot for your time.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Symbolic Math Toolbox finden Sie in Help Center und File Exchange

Produkte


Version

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by