How could I solve this error?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Bajdar Nouredine
am 20 Aug. 2021
Beantwortet: darova
am 23 Aug. 2021
this code does not have any problem with respect to r and t, but when I add interval for t and r it gives this error
thanks for helping
B=(2/pi)^(1/2);
r1=0.00001;
k=0.42;
Cp=3600;
g=1000;
rho=1048;
Tb=37;
qm=300;
w=0.0005;
ra=0.01;
%%
c=w*rho*Cp;
r_distance=ra*2;
time_total=1;
dr=r_distance/10;
dt=0.1;
rmesh=0:dr:r_distance;
tmesh=0:dt:time_total;
rskip=2;
tskip=2;
number_iterations=2;
nr=length(rmesh);
nt=length(tmesh);
V=zeros(nt,nr);
for i=1:nt
for j=1:nt
for m=1:number_iterations
q = int((((B*(rp*sqrt(c))^(-0.5)*sin(rp*sqrt(c))/(sqrt(rp)*B*(sqrt(c))^(-0.5)*sin(sqrt(c)))))-1)*rp*sin(m*pi*rp),rp,0,1); % the integral r prime from 0 to 1
first_term = symsum((exp((m*pi)^2+c)*(-tmesh(j)))*sin(m*pi*rmesh(i))*q, m, 1, 10); % a summation
end
end
end
Error using sym/symsum (line 52)
Cannot compute the sum with respect to '1'. The summation index must be a symbolic variable.
Error in test (line 36)
first_term = symsum((exp((m*pi)^2+c)*(-tmesh(j)))*sin(m*pi*rmesh(i))*q, m, 1, 10); % a summation
7 Kommentare
Akzeptierte Antwort
darova
am 23 Aug. 2021
You are using the same variable as in for loop. That why you have an error
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Calculus finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!