What are the frequencies when N in fft(x,N) is odd?

I know when N is even, fft(x,N) corresponds to frequencies 0,df,...,N/2*df,-(N/2-2)*df,...,-df.
What about if N is odd?

 Akzeptierte Antwort

Honglei Chen
Honglei Chen am 10 Jul. 2014
Bearbeitet: Honglei Chen am 10 Jul. 2014
In general, you can do it as
f = (0:N-1)*fs/N
If you want to map it to negative frequencies
if N is even
f(N/2+1:end) = f(N/2+1:end)-fs % sample -fs/2
or
f(N/2+2:end) = f(N/2+2:end)-fs % sample fs/2
if N is odd
f((N+1)/2+1:end) = f((N+1)/2+1:end)-fs
HTH

5 Kommentare

Ray Lee
Ray Lee am 10 Jul. 2014
why there are different two for even N?
Honglei Chen
Honglei Chen am 10 Jul. 2014
Bearbeitet: Honglei Chen am 10 Jul. 2014
-fs/2 and fs/2 are the same point due to periodicity. The difference is really just which one you want to display in your axis
Ray Lee
Ray Lee am 10 Jul. 2014
the output of fft is unique, but in the two formulae, the f axis is shifted by one point.
Honglei Chen
Honglei Chen am 10 Jul. 2014
Bearbeitet: Honglei Chen am 10 Jul. 2014
That's not true. Only one point is changed, from fs/2 to -fs/2 and because the result is periodic, they are indeed the same so you can mark it either way
To be clear, if you are using fftshift on your FFT data and N is even, use the first option (repeated here):
f(N/2+1:end) = f(N/2+1:end)-fs % sample -fs/2

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Weitere Antworten (1)

Michael scheinfeild
Michael scheinfeild am 10 Jul. 2014
if x is ampled at fs you can generate frequency vector use
freqvec=linspace(0,fs,N);

3 Kommentare

Ray Lee
Ray Lee am 10 Jul. 2014
I don't think so. The negative frequencies are missing.
This is incorrect. linspace always sample the last one, which you don't want.
@Honglei Chen Hi, can i know why last sample should not be taken into?

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