struct and cell ,is there a way like dictionary in struct

 if true
 end
station = struct(...
'name', {'CD2','GYA','LZH','GOM','XAN'},...
'Jingdu',{103.76 ,106.66,103.84,94.81,108.92},...
'Weidu',{30.91,  26.46,  36.09, 36.20, 34.03});
p={'CD2','GYA','LZH','GOM','XAN'};

now i pick one from p,how can i get the one 's Jingdu?

Answer 1

[Jos (10584)]

You mean something like this?

station = struct(...
'name', {'CD2','GYA','LZH','GOM','XAN'},...
'Jingdu',{103.76 ,106.66,103.84,94.81,108.92},...
'Weidu',{30.91,  26.46,  36.09, 36.20, 34.03});
p={'CD2','GYA','LZH','GOM','XAN'};

K = 2 ; % pick one

TF = strcmp({station.name}, p{K}) % true when station.name equals p{K}
Result = [station(TF).Jingdu]

[Roger]

yes，thanks very much

Answer 2

[Roger]

is there a way like dictionary in struct

[Walter Roberson]

[tf, k] = ismember('GYA', station.name);
if tf
 disp(station.Jingdu(k))
else
 disp('no match')
end