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What's wrong with my feature extraction code?

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Explorer
Explorer am 12 Feb. 2014
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
I am getting same descriptors for different images.
I tested it by:
image1 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\A.jpg');
image2 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\B.jpg');
v1=Descrip(image1);
v2=Descrip(image2);
SUM=sum(v1-v2)
_____________________________________________________________________________________
Output :
SUM =
0
  1 Kommentar
Explorer
Explorer am 12 Feb. 2014
There is something wrong in Descrip.m because I am getting zero for SUM=sum(v1-v2). Ideally, it should not be zero.

Antworten (2)

David Young
David Young am 12 Feb. 2014
Descrip writes then reads contour.jpg, and then computes the result from that. One way to set about debugging would be to see whether contour.jpg is different for the two images. That will help pin down where the problem lies.
  4 Kommentare
Explorer
Explorer am 12 Feb. 2014
Bearbeitet: Explorer am 12 Feb. 2014
But sum is not equal to equal when I replace "1" with "2" in line # 57 of Descrip.m and Descrip2.m
i.e
________________________________________________________________________
Original
thisBoundary = boundary{1}; % Or whatever blob you want.
________________________________________________________________________
Replaced
thisBoundary = boundary{2}; % Or whatever blob you want.
David Young
David Young am 13 Feb. 2014
The idea was that you run Descrip with one input image, look at contour.jpg, run it again with the other input image, and look at contour.jpg again. Are they different?

Image Analyst
Image Analyst am 12 Feb. 2014
Bearbeitet: Image Analyst am 12 Feb. 2014
Don't use image as a variable name - it's the name of a built-in function.
  5 Kommentare
Image Analyst
Image Analyst am 13 Feb. 2014
If image A equals image B then I think they should be the same. You didn't attach either image so only you can know that. What did stepping through with the debugger reveal to you?
Walter Roberson
Walter Roberson am 13 Feb. 2014
Watch out for the case where v1 and v2 are being returned as unsigned integers; in that case if v2 > v1 you would get "clipping" at 0 instead of getting a negative number.

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