If I am have this code as example
while(A>0.0000001);
statment
.
.
.
end
How can save value of A to each iteration until reach 0.0000001?
I mean there is (A) at first iteration, (A) at second iteration,and so on

 Akzeptierte Antwort

Walter Roberson
Walter Roberson am 4 Dez. 2013

1 Stimme

K = 1;
A(K) = .... some initial value ...
while( A(K) >0.0000001)
statment
.
.
.
K = K + 1;
A(K) = new value for A
end

3 Kommentare

Mary Jon
Mary Jon am 4 Dez. 2013
How can I know the time taken by A to reach convergence in seconds
dpb
dpb am 4 Dez. 2013
doc tic % toc
Mary Jon
Mary Jon am 4 Dez. 2013
Thank you dpb

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Weitere Antworten (2)

Jeremy Wurbs
Jeremy Wurbs am 4 Dez. 2013

1 Stimme

If you know how long you're going to iterate for, something like:
numIter = 10;
A_vec = zeros(numIter,1);
A = 10; cnt = 1;
while(A>0)
A_vec(cnt) = A;
A = A-1;
cnt = cnt+1;
end
If you don't know how long you will iterate for you might not be able to preallocate efficiently (which will greatly slow things down). That said, it is legal to do the following:
A_vec = [];
A = 10;
while(A>0)
A_vec(end+1) = A;
A = A-1;
end
dpb
dpb am 4 Dez. 2013

1 Stimme

A=[];
iter=0;
while...
iter=iter+1;
A(i)=...;
...
end
NB that if iter grows very large the reallocation every iteration above may begin to noticeably slow down the execution. To minimize this, start by preallocating A and filling. You'll have to check for overflow and reallocate if needed or make the initial size large enough to never be exceeded in which case you can then truncate when done.
N=100;
A=zeros(N,1);
iter=0;
while...
if iter==N, A=[A; zeros(1,N)]; N=N+N; end % add another chunk
iter=iter+1;
A(i)=...;
...
end

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