how do i generate a 1X4 matrix with until the sum of the matrix =100

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Austin
Austin am 5 Nov. 2013
Beantwortet: Image Analyst am 5 Nov. 2013
how do i generate a 1X4 random matrix until the sum of the matrix equals to 100
with the following condition: (each time the matrix is generated, the last element of the newly generated 1X4 matrix being the first element of last generated 1X4 matrix?) (advise using persistent variables)
  2 Kommentare
Azzi Abdelmalek
Azzi Abdelmalek am 5 Nov. 2013
What kind of random numbers, integers? real? its maximum value?
Austin
Austin am 5 Nov. 2013
Bearbeitet: Austin am 5 Nov. 2013
sorry, its real. no maximum value given, each time the sum of the 4 elements does not add up to 100,it regenerates 4 real numbers again..
a=100*rand(1,4) if sum(a)~=100
.....

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Antworten (4)

Azzi Abdelmalek
Azzi Abdelmalek am 5 Nov. 2013
The probability to fit your conditions is very small, you can run your code all the year, it's not obvious to get the result.

Image Analyst
Image Analyst am 5 Nov. 2013
Try this:
clc;
maxLoops = 1000
loopCounter = 1;
while loopCounter <= maxLoops
theArray = randi(97, 1, 4);
value = sum(theArray);
if value == 100
fprintf('The array = [%d, %d, %d, %d], found after %d tries.\n',...
theArray(1), theArray(2), theArray(3), theArray(4), loopCounter);
break;
end
loopCounter = loopCounter + 1;
end
if loopCounter >= maxLoops % The failsafe kicked in
% Not found.
fprintf('Sum of 100 not found after %d tries.\n', maxLoops);
end
  3 Kommentare
Azzi Abdelmalek
Azzi Abdelmalek am 5 Nov. 2013
In his comment, he asks for real numbers

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Simon
Simon am 5 Nov. 2013
Hi!
Another way may be to create 4 random numbers, take what is missing upto 100 and add to the numbers:
% random numbers
a = 100*rand(1,4);
% missing part
miss = 100 - sum(a);
% choose one possibility
% add to numbers, possibility 1 (linear)
a = a + miss/4;
% add to numbers, possibility 2 (proportional)
a = a + miss*(a/sum(a))
% add to numbers, possibility 3 (???)

Image Analyst
Image Analyst am 5 Nov. 2013
Here's a way where you can specify how close you want to get to 100 using floating point numbers. Like Azzi and I said, there's virtually no chance you'll ever hit 100 exactly out to the millionth decimal place. My code below will find numbers that get you to within 0.01, which you can change to get closer if you want.
clc;
maxLoops = 100000
loopCounter = 1;
while loopCounter <= maxLoops
theArray = 97*rand(1, 4);
theSum = sum(theArray);
if abs(theSum - 100) < 0.01
fprintf('The sum = %.5f.\nThe array = [%g, %g, %g, %g], found after %d tries.\n',...
theSum, theArray(1), theArray(2), theArray(3), theArray(4), loopCounter);
break;
end
loopCounter = loopCounter + 1;
end
if loopCounter >= maxLoops % The failsafe kicked in
% Not found.
fprintf('Sum of 100 not found after %d tries.\n', maxLoops);
end

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