potential issue with fscanf new line character, the newline character is /n coming from a c background i was trying \n.
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fid = fopen("Files.txt","r");
string = fscanf(fid,"%s\n")
fclose(fid);
fid = fopen("Files.txt","r");
string = fscanf(fid,"%s/n")
fclose(fid);
fprintf("Not consistent newline char\n(Used the backslash here not forward slash)\n");
3 Kommentare
Stephen23
am 5 Apr. 2024 um 13:24
Bearbeitet: Stephen23
am 5 Apr. 2024 um 13:25
"The desired result is the same as string = fscanf(fid,"%s/n") I beleive this is a bug because clearly the newline character is \n, as is the case in fprintf and in C's implementation of fscanf."
Nothing you have shown looks like a bug, nor does your expectation match the documented behavior of FSCANF:
- your example with "%s\n" reads some non-whitespace text until the end of the line, then reads a newline, and then repeats this many times (because there are no non-matching characters to stop the parsing).
- your example with "%s/n" reads some non-whitespace text and then stops because there is no literal match for the literal characters "/" and "n".
This behavior is explained in the FSCANF documentation:
particularly where it explains at the topc of the page "The fscanf function reapplies the format throughout the entire file and positions the file pointer at the end-of-file marker. If fscanf cannot match formatSpec to the data, it reads only the portion that matches and stops processing."
So far everything is exactly as documented and expected. So far you have not provided an explanation of why you expect some behavior different to that given in the FSCANF documentation.
Antworten (1)
Image Analyst
am 3 Apr. 2024 um 14:37
2 Kommentare
Image Analyst
am 6 Apr. 2024 um 18:10
Why? I don't know anyone who uses or assumes /n as the new line character. Everyone uses \n as far as I know. So again, why do you want to use /n? And it's not a bug because like @Stephen23 said, it quits reading if it doesn't see a /n -- that's normal and expected.
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